WebJan 1, 2024 · GATE 2024 Civil Bits & Bytes (1116 Practice Questions With Solutions) Volume 2 Paperback – 1 January 2024 by Subject Experts of the ACE Engineering Academy (Author) 22 ratings See all formats and editions Paperback ₹413.00 1 New from ₹413.00 Save Extra with 3 offers No Cost EMI: Avail No Cost EMI on select cards for … WebA certain processor uses a fully associative cache of size 16 kB, The cache block size is 16 bytes. Assume that the main memory is byte addressable and uses a 32-bit address. How many bits are required for the Tag and the Index fields respectively in the addresses generated by the processor?
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WebOct 17, 2024 · The packet bytes pane shows the data of the selected packet in the “Packet List” pane in a hex dump style. A “hex dump” represents a binary data stream where the contents of that stream are displayed as hexadecimal values. It divides the binary data into 8-bit bytes and displays the value of each byte as a two-digit hexadecimal number. WebDec 16, 2024 · GATE 2024 was successfully held on February 5, 6, 12, and 13. On March 17, 2024, IIT Kharagpur published the GATE 2024 Question Papers for all 29 papers along with the official answer keys. Candidates can download and practise these branch-specific GATE Previous Year Question Papers from this list. how many episodes of soa are there
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WebApr 28, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. ... GATE CS & IT 2024; Data Structures & Algorithms in JavaScript; Data Structure & Algorithm-Self … WebA sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of an acknowledgment is 100 bytes and the transmission rate at the receiver is 8 Kbps. The one-way propagation delay is 100 milliseconds. WebFeb 14, 2024 · Answer: (D) Explanation: Virtual address size = 32 bits Physical address size = 36 bits Physical memory size = 2^36 bytes Page frame size = 4K bytes = 2^12 bytes No. of bits for offset (or number of bits required for accessing location within a page frame) = 12. No. of bits required to access physical memory frame = 36 – 12 = 24 high waist bikini panties